-2m^2-15m=7

Solution for -2m^2-15m=7 equation:

-2m^2-15m=7

We move all terms to the left:

-2m^2-15m-(7)=0

a = -2; b = -15; c = -7;
Δ = b2-4ac
Δ = -152-4·(-2)·(-7)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-13}{2*-2}=\frac{2}{-4}
=-1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+13}{2*-2}=\frac{28}{-4}
=-7
$